C-output

Question

Comments

@VS ji,

Mentioned diagram requires small correction.

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S is the first element itself. It doesn't point to an array

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try this

Answer 1

Answer is 1006.

In the mentioned problem S represents the base address of ths $s[0]^{th}$ element. But when &S is used it represents the base address of entire set. So (&S+1) represents address after skipping one set. Here one set contains 6 elements of size 1 B. :)

For more clarity refer ->

https://ideone.com/dUcgjo (Here int is 4B and array is 2D)

https://ideone.com/jv5rf3 (Here pointer is 8B )

Comments

General rule; for any pointer arithmetic (array is a pointer):

If $p$ is a pointer, $p +$ a constant $d$ numerically equals $p + d\times sizeof(*p)$.

Now, when someone says sizeof int is 1 in C language; even if it is an assumption, I can't continue with the question -- because C language requires sizeof int to be at least 2.