# floating point range

0 votes
297 views

Plz xplain

retagged

## 1 Answer

1 vote
(a) Largest positive value:

This happens when all significant (mantissa) bits are 1, and the exponent bits are all 1.

$=(b)^{p-1} -1\times (b)^{X-q}$

Smallest positive value:

This happens when the LSB of mantissa is 1 and the exponent bits are 0 so that subtracting the bias gives the largest negative value possible for exponent
$=1 \times (b)^{-q}$
0

I have doubt regarding Floating point repsentation i cannot understand when we take the bias to 2^6=64 normalisation is said to occur when the number is in the form of 0.1bbbbb but normalisation is said to occur when bias is 63 then normalisation is said to occur when the number is of the form 1.BBBBB

This is from the solution maual to stallings

also many youtube videos also say normalisaton of fp is reprsentaion in 0.11111 form

see this

could you plz expain

0

@Arjun sir I am not able to understand why $(b)^{p-1}$ why not $(b)^{p}$ ? Can you kindly explain?

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