Vertical microprogrammed CU supports 256 instructions,
The system is using 8 flag conditions,
contains 48 control signals. ,
Each instruction on an avg requires 16 micro-operations. ,
CU support 256 instructions where each instruction requires 16 MO $\therefore$ there will be $256 * 16 = 4096 \ CW$
Now one Control word structure will be something like this :
3 For flags |
6 For signal (Vertical) |
12 For addressing next CW |
$\therefore 21 \ bits \ for \ one \ CW$
Size of Control MEmory = $4096 * 21 = 86016bits \ or\ 10752Bytes$