1 votes 1 votes Consider a wireless link, where the probability of packet error is 0.6. To transfer data across the links, Stop and Wait protocol is used. The channel condition is assumed to be independent from transmission to transmission. The average number of transmission attempts required to transfer x packets is 500. The value of x is _______. Computer Networks stop-and-wait computer-networks made-easy-test-series + – Shubham Kumar Gupta asked Dec 16, 2017 edited Mar 7, 2019 by Aditi Singh Shubham Kumar Gupta 1.2k views answer comment Share Follow See 1 comment See all 1 1 comment reply Ashwin Kulkarni commented Dec 16, 2017 reply Follow Share X is 200 500 = x/1-p 500 = x/1-0.6 x=200 1 votes 1 votes Please log in or register to add a comment.
3 votes 3 votes number of packet be x(given) probability of error=0.6 the average number of retransmission number=500(given) 500=x+0.6*x+0.6*0.6*x+0.6*0.6*0.6*x+.............................................infinite GP 500=x/1-0.6 x=200 packet BASANT KUMAR answered Oct 27, 2018 BASANT KUMAR comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Packet without error prob=0.4 In 100 packets 40 packets are reaching safely To reach 500 safely 500/40 = 8 Total attempts 8*100=800 guptashekhar54 answered Jul 22, 2018 guptashekhar54 comment Share Follow See 1 comment See all 1 1 comment reply bhavnakumrawat5 commented Jul 31, 2018 reply Follow Share what will be right ans...? I got 200 0 votes 0 votes Please log in or register to add a comment.