10 level 0
8 5 level1
3 2 level 2
after insertion of...
10 level 0
8 5 level1
3 2 1 level 2
heap property is still satisfied... then we will insert next 7
10 level 0
8 5 level1
3 2 1 7 level 2
here 5<7 then swap 7 & 5....
10 level 0
8 7 level1
3 2 1 5 level 2
.....
now traverse...10,8,7,3,2,1,5