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2 Answers

Best answer
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11 votes
$10$ tosses of coin are there.

Probability of head = $0.4$

Probability of tail = $0.6$

Probability of at least one head $=1- P{_\text{no head occur}} ={1-(0.6)^{10}}.$

Correct Answer: $C$
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2 votes
2 votes
n = 10

Using Binomial expansion,

probability of getting success(head) = 0.4

probability of getting failure(tail) = 1-0.4 = 0.6

probability of getting at least one head P(x >=1) = 1 – P(x=0) = 1 – $\binom{10}{0}(0.4)^{0}(0.6)^{10-0}$ = 1 – $(0.6)^{10}$

Answer C
Answer:

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