0 votes 0 votes What is the measure of the radius of the circle that circumscribes a triangle whose sides measure 9, 40 and 41 ? rfzahid asked Dec 18, 2017 rfzahid 760 views answer comment Share Follow See 1 comment See all 1 1 comment reply Ashwin Kulkarni commented Dec 18, 2017 reply Follow Share The triangle is Pythagoras. with hypo as 41. diameter subtends 90 degree angle on circumference of a circle. Hence diameter = 41 radius = 20.5 2 votes 2 votes Please log in or register to add a comment.
Best answer 5 votes 5 votes 40^2 + 9^2 = 41^2 = 1681 Hence it satisfies Pythgorus theorem. As we know that a traingle inside a circle can be right angled iff the hypo of the right angled traingle is diameter . So Diameter = 41 Unit Radius = 41/2 = 20.5 Unit Saurav answered Dec 18, 2017 selected Dec 18, 2017 by rfzahid Saurav comment Share Follow See all 0 reply Please log in or register to add a comment.