MadeEasy Test Series: Operating System - Virtual Memory

Question

Consider a machine 32 MB physical memory and 32 bit virtual address space. If the page size is 8 KB, what is the approximate size of the page table in MB?

It was in numerical type and i filled .75 as the answer,but given answer is 1. What should be the correct answer?

Comments

Yes we have to write exact value

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I have a small doubt here What if we consider the mem as Byte addressable then , surely an entry if 12 bits will take 2 mem cells i.e. 16 bits = 2 Bytes

In that case ans 1 MB

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I think if we need to approximate 12 bits to 2Bytes then correct term will be Byte Aligned.See https://gateoverflow.in/39601/gate2016-2-31

Answer 1

Pages 2^19

frames = 2^12

PTE = 12 bits

but memory  is byte addressable so we have to allocate 2 byte space for 12 bits

PTS = 2^19*16 = 2^23 bits =2^20 byte =1 MB