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A disk rotates at a speed of 3600 rpm. It has 4000 cylinders, 16 surface and 206 sectors per tracks. Track storage capacity is 2048 bytes. What is the average latency time (in msec) and data transfer rate (in kbps) respectively.

A 16.66, 12.28

B 8.33, 196.48

C 16.66, 196.48

D 8.33, 12.28

Given answer is d, but i got 8.33 , 960Kbps
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1 rotation-------------60/3600 sec = 1/60sec

Average Latency = 1/60*2 = 8.33msec

in, 1/60sec------------------------2048 B data read by head

then in, 1sec ---------------------------- x

x=122880 byes/sec or x = 122.88 KBps

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