Operating system memory closed

Question

There are 5 processes having an average size of 100k. Average size of hole is 60k. Percentage of memory wasted in holes?

1. 76
2. 37
3. 23
4. None

Comments

it should be $\frac{60*5}{160*5} = 37.5$%

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for every ..process p ..100k usefull +60Waste(hole)....

%of wastage memory...60/160 *100 ....

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made easy psu book

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Caption