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Suppose,

size of a full window is 24 Kb.

There is no congestion.

1 MSS = 2 Kb.

RTT = 10 ms

How long does it take to send the first full window?

Approach 1) 2 | 4 | 8 | 16 | 24 = 4 RTTs =4 * 10 ms = 40ms  

Approach 2) 2 | 4 | 8 | 16 | 24 |  = 5 RTTs = 5 * 10 ms = 50ms

 Which approach is correct?

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