Suppose,
size of a full window is 24 Kb.
There is no congestion.
1 MSS = 2 Kb.
RTT = 10 ms
How long does it take to send the first full window?
Approach 1) 2 | 4 | 8 | 16 | 24 = 4 RTTs =4 * 10 ms = 40ms
Approach 2) 2 | 4 | 8 | 16 | 24 | = 5 RTTs = 5 * 10 ms = 50ms
Which approach is correct?