3 votes 3 votes A link has a transmission speed of 500 × 106 bpsec. Assume acknowledgment has negligible transmission delay, and its one way propagation delay is 2 sec. Also assumes that the processing delays at nodes are also negligible. If data packet size is 107 bits, then the efficiency of Go-Back-7 protocol is _______ (in %) Computer Networks computer-networks go-back-n + – Rohit Gupta 8 asked Dec 22, 2017 Rohit Gupta 8 2.0k views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments abhishek tiwary commented Dec 22, 2017 reply Follow Share yes 3.48 0 votes 0 votes Sunit Acharya commented Jan 25, 2018 reply Follow Share Yes, this is my doubt too. In the video he "7 bits is given, so we can go to 127". I think he meant something like 2 raised to the power of 7 or sth, still that comes to 128. 0 votes 0 votes meena95 commented Jan 31, 2018 reply Follow Share they don't know what is 'n' means in GBN 0 votes 0 votes Please log in or register to add a comment.
Best answer 7 votes 7 votes Tp = 2 sec Tt = Packet Size / Bw = 10^7 bits / 500 * 10^6 bits per sec = 0.02 sec Efficiency = W / 1+2a = 7 / (1 + 2 * 2/0.02) = 0.0348 = 0.0348 * 100 = 3.48% Yogesh Mandge answered Dec 22, 2017 selected Dec 22, 2017 by Rohit Gupta 8 Yogesh Mandge comment Share Follow See all 0 reply Please log in or register to add a comment.