6 Mb→1 sec
(19.5MB *8) Mb→( time for computer to transmit data)??
time for computer to transmit data
= total bits / max trans rate
= (19.5 MB * 8 bits/byte) / 6 Mbps
= 156 Mb / 6 Mb/s
= 26 s
4 Mb → 1 sec
actual data sent on network ?? → 26 sec
actual data sent on network in 26 s = network rate * 26s
= 4 Mb/s * 26s
= 104 Mbits = 13 Mbytes
bucket size = 19.5 MB - 13 MB = 6.5MB(or 52Mb)