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Sender transmission rate is...6Mbps ...time taken by sender to transmit 19.5 MB is  ..19.5*8/6  : 26

and maximum output rate of bucket is 4Mbps...outgoing amount of data in 26sec time is  4*26 /8 : 13MB

Data remaining in bucket is ...19.5-13:-6.5

:- In burst case queue must have capacity to hold 6.5MB of Data

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6 Mb→1 sec
        (19.5MB *8) Mb→( time for computer to transmit data)??
time for computer to transmit data
    = total bits / max trans rate
     = (19.5 MB * 8 bits/byte) / 6 Mbps
= 156 Mb / 6 Mb/s
= 26 s
 
4 Mb → 1 sec
actual data sent on network ?? → 26 sec
actual data sent on network in 26 s = network rate * 26s
= 4 Mb/s * 26s
= 104 Mbits = 13 Mbytes
bucket size = 19.5 MB - 13 MB = 6.5MB(or 52Mb)

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