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A system has  CPU organized in the form of general register organization consisting of 16 registers, each storing 32 bit data. assume ALU have 35 operations . how many multiplexer are needed and what is the size of mux.
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As size of each register is 32 bit . we are going to give each bit of register to different MUX thus total 32 MUX will be required .

There are 16 registers thus 16 different bit will be present in 1 MUX thus size of the MUX will be 16*1.

In general if there are n register of size x bit then

 no. of MUX = x

size of MUX=n*1
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