2 votes 2 votes How many 5 digit number are possible so that in each of these number every digit is greater than digit on its right? Pooja Palod asked Oct 5, 2015 Pooja Palod 302 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes i solved like this first lets take number from 1 to 9 then we can select any 5 numbers in 9C5 ways but we can arrange them only in one way. now including 0 we can place it at only last position since at any other position it would not satisfy the condition. so remaining place will be filled by all 9 digits that is 9C4 so total combination = 9C5 + 9C4 = 252. Umang Raman answered Oct 5, 2015 Umang Raman comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Once you pick 5 different digits, there is only one way to arrange them so that the digits are decreasing. I would view the answer as (9C5), but of course this is equal to (9C4). Kaluti answered Sep 5, 2017 Kaluti comment Share Follow See all 0 reply Please log in or register to add a comment.