1 votes 1 votes Number of multi-graphs possible with 4 vertices and at most 2 edges between each pair of vertices is ________________ Graph Theory ace-test-series graph-theory counting + – Satyam Rohela asked Dec 25, 2017 • edited Mar 7, 2019 by Rishi yadav Satyam Rohela 955 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Show 3 previous comments Shubhanshu commented Dec 25, 2017 reply Follow Share Yes, it should be 729. Previously, I thought it is "at most 2 edges in the multigraph." 0 votes 0 votes Neeraj Mehta commented Dec 26, 2017 reply Follow Share is it 665 ? 0 votes 0 votes Satyam Rohela commented Dec 27, 2017 reply Follow Share There will be 4C2 = 6 possible ways to select a pair of vertices from 4 vertices. And between every pair there will be 0,1 or 2 vertices. Hence, for 6 pairs 36 = 729 possible combinations. Therefore, the answer is 729. 1 votes 1 votes Please log in or register to add a comment.
0 votes 0 votes But why we are not subtracting no. of simple graphs from 729 i.e shouldn’t answer be like 729-(no.of simple graphs)=665. Karan Negi answered Dec 29, 2020 Karan Negi comment Share Follow See all 0 reply Please log in or register to add a comment.