2 votes 2 votes Akash Mittal asked Dec 25, 2017 Akash Mittal 251 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Ashwin Kulkarni commented Dec 25, 2017 reply Follow Share Is it option C? for Any value? 0 votes 0 votes Akash Mittal commented Dec 25, 2017 reply Follow Share yes its C. 0 votes 0 votes Akash Mittal commented Dec 25, 2017 reply Follow Share explaination? 0 votes 0 votes Ashwin Kulkarni commented Dec 25, 2017 reply Follow Share I solved using linear non homogenous equation method. just made 3 equations, c1 + 5c3 = 2 -2c1 + c2 -6c3 = -1 c2+4c3 = 3 Then you will get r(AB) = r(A) < n and also r-n =1. Hence take 1 constant. After transformations, c1 + 5c3 = 2 c2+4c3 = 3 since r-n =1 take one constant c3 =k, c2 = 3-4k, c1 = 2-5k 1 votes 1 votes Please log in or register to add a comment.