P(0T)= 0.4 ie probability of 0 transmitted.
P(1T) = 0.6
P(1R) = probability of receiving 1.
case 1 :if 0 is transmitted than we can receive it as 1
case 2 : if 1 is transmitted than we can receive it as 1
P(1R) = 0.4*(1-.95) + 0.6 *.90 = .56
P(1T $\bigcap$ 1R) = 0.6*.9=.54
P(1T/1R) = .54/.56 = 0.96