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+1 vote
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please explain how to start solving such circuital questions..I always get confused..plzz help someone asap.

What will be the final output?

in Digital Logic by (403 points)
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0
Where is the question?
0
see i have posted again..now it is visible...plzz explain na..
0

I don't know in what format solution is given but i got this answer.

0

The solution given was this..

how did we get this..

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I have mugged up with C & D. I have taken LSB and MSB differently. but method is same.
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in this solution how they have taken I0 and I3.

even i got same answer as yours but in test series ans was different..
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Why there is 0 and 1 in front of A and B in the decoder? Does it imply anything?
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even i dnt know....

1 Answer

0 votes

Decoder Output

D0 = (A'.B'), D1 = (A'.B), D2 = (A.B'), D3 = (A.B)

Mux Output

F(A, B, C, D) = D'.C'.(A'.B) + D'.C(A'.B') + D.C'.(A.B) + D.C.(A.B')  

by Active (2.7k points)

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