1 votes 1 votes please explain how to start solving such circuital questions..I always get confused..plzz help someone asap. What will be the final output? Digital Logic made-easy-test-series digital-logic decoder multiplexer + – sunita24 asked Dec 28, 2017 • retagged Mar 14, 2019 by adeebafatima1 sunita24 930 views answer comment Share Follow See all 8 Comments See all 8 8 Comments reply gauravkc commented Dec 28, 2017 reply Follow Share Where is the question? 0 votes 0 votes sunita24 commented Dec 28, 2017 reply Follow Share see i have posted again..now it is visible...plzz explain na.. 0 votes 0 votes Ashwin Kulkarni commented Dec 28, 2017 reply Follow Share I don't know in what format solution is given but i got this answer. 0 votes 0 votes sunita24 commented Dec 29, 2017 reply Follow Share The solution given was this.. how did we get this.. 0 votes 0 votes Ashwin Kulkarni commented Dec 29, 2017 reply Follow Share I have mugged up with C & D. I have taken LSB and MSB differently. but method is same. 0 votes 0 votes sunita24 commented Dec 29, 2017 reply Follow Share in this solution how they have taken I0 and I3. even i got same answer as yours but in test series ans was different.. 0 votes 0 votes gauravkc commented Dec 29, 2017 reply Follow Share Why there is 0 and 1 in front of A and B in the decoder? Does it imply anything? 0 votes 0 votes sunita24 commented Dec 29, 2017 reply Follow Share even i dnt know.... 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Decoder Output D0 = (A'.B'), D1 = (A'.B), D2 = (A.B'), D3 = (A.B) Mux Output F(A, B, C, D) = D'.C'.(A'.B) + D'.C(A'.B') + D.C'.(A.B) + D.C.(A.B') hacker16 answered Dec 28, 2017 hacker16 comment Share Follow See all 0 reply Please log in or register to add a comment.