1 votes 1 votes Find the number of literals in minimal SOP for the function f(a,b,c,d)=π(0,1,2,6,8,10,11,12) sol: f(a,b,c,d)=Σ(3,4,5,7,9,13,14,15) Minimal SOP is a’cd+ac’d+abc+a’bc’ a’ (b+b')cd+a(b+b') c’d+abc (d+d')+a’bc’(d+d')+bd(a+a')(c+c') 2+2+2+2+4=12 this is right solution? mohitbawankar asked Dec 29, 2017 mohitbawankar 258 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply Ashwin Kulkarni commented Dec 29, 2017 reply Follow Share Why to expand the solution? literals are simply a’cd+ac’d+abc+a’bc’ = 12 (count all variables in its compliment or uncomplimented form) 0 votes 0 votes mohitbawankar commented Dec 30, 2017 reply Follow Share ???? 0 votes 0 votes Please log in or register to add a comment.