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In synchronous transmission, 5 eight bit characters are included in 30 eight bit information characters. If bit rate of sender is 4200 bits/sec, what is the bit rate of receiver (in bits per sec)?
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In synchronous transmission

  • Sync characters are added before and after of complete character stream.
  • transmission time and receiving time should be same ie, synchronized.

Transmission time= data size / transmission rate =30*8 /4200 = 240/4200 sec

But extra 5 eight bit sync characters also will be added for synchronization, and receiver has to receive whole message within same time.

Receiver bit rate = (data size+ sync character size)/receiving time

= (30*8+5*8)/(240/4200)    //****bcz receiving time= transmission time

= 4900 bits per sec

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