291 views

1 Answer

Best answer
8 votes
8 votes

Answer is 392.

Total relations = 29 = 512

Relations which are neither Ref, nor Symmetric means we have to do Total Realtions - (Symmetric U reflexive)

Number of Reflexive relations = We have choice only on non-diagonal elements hence 2n^2-n = 29-3 = N(R) = 26

Number of symmetric relations = We have choice for diagonal elements as well as symmetric pairs = 2n * 2(n^2-n)/2 = N(S) = 23 * 23 = 26

Number of relations which are both symmetric as well as Reflexive = only choice about pairs (Diagonal elements must be there) = N(R $\cap$ S) = 2(n^2-n)/2  = 23

Hence N(R U S) = N(R) + N(S) - N(R $\cap$ S)

= 64 + 64 - 8 = 120

Hence niether Ref, nor symmetric = 512-120 = 392.

selected by

Related questions

2 votes
2 votes
1 answer
1
h4kr asked Dec 27, 2022
358 views
Is the statement true that all reflexive relations are anti-symmetric?
0 votes
0 votes
0 answers
2
Yamini_learner asked Sep 26, 2022
319 views
Let R be a relation.Why $R^2 oR^2 !=R^4$ while $R^3 oR =R^4$?Please explain.
1 votes
1 votes
1 answer
3
0 votes
0 votes
1 answer
4
srestha asked Mar 7, 2019
861 views
Let $A=\left \{ 1,2,3 \right \}$. Number of relation on $A$ which are neither reflexive, nor irreflexive but symmetric is ___________Ans given 48but I got 8Please verify