Associative mapping in cache

Question

If main memory  $=128 \ KB$ and cache memory is of $2KB$ with $16B$ lines .and uses associative mapping .
What would be the # of bits used for Tag for each block?

Comments

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clearly none of the options are matching !

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Yes!!

Answer 1

the correct answer is option a

main memory size = 128 kb = 2 ^7 * 2^10  = 2^17 bytes

cache memory size = 2 kb = 2^10 bytes

no of lines = 16 bytes

cache offset = cache memory size \ no of lines = 2^10\2^4 = 2^6 bytes

number of bits in cache offset = 6 bits

as total main memory size = 17 bits

tag bits = 17 - 6 = 11 bits