4 votes 4 votes It should be 1 and 3 ?? please correct me if I'm wrong. Calculus engineering-mathematics calculus + – Ashwin Kulkarni asked Jan 1, 2018 Ashwin Kulkarni 1.1k views answer comment Share Follow See all 20 Comments See all 20 20 Comments reply Show 17 previous comments Anjan commented Jan 1, 2018 reply Follow Share $f(x) = x^2 - 6x + 666$ $f'(x) = 2x-6$ 1) Find critical points, here $3$ is critical point. 2) find sign in the intervals $(-\infty,3),(3, \infty)$ 3) take any values say x=1 in $(-\infty,3)$ then $f'(x)$ is -ve function is decreasing 4) take any values say x=4 in $(3,\infty)$ then $f'(x)$ is +ve function is increasing. 1 votes 1 votes srestha commented Jan 1, 2018 reply Follow Share yes a) and c) both correct 1 votes 1 votes Shubhanshu commented Jan 7, 2018 reply Follow Share Yes, I think both a and c are correct. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes it will be easy by solving through wavey curve a,c are the correct options shuham kumar answered Sep 20, 2022 shuham kumar comment Share Follow See all 0 reply Please log in or register to add a comment.