Size of the ROM

Question

A $\text{ROM}$ is used to store the table for Addition of $2$ number of $16$ bit unsigned integers. The size of the $\text{ROM}$ required for the above application in Giga Bytes is _______________.

Comments

https://gateoverflow.in/188500/block-replacement-in-cache

Bro,plz have a look on this one.

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Ohh thanks @shubham

I have calculated in bits :(

68Gb = 8.5GB

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Just small additional info: For all such kinds of questions, Size of ROM = 

Size of 1 result * Number of all possible results

Here, same question but with multiplication https://gateoverflow.in/2725/gate1996-1-21

Answer 1

 

 total entry=2¹⁶*2¹⁶=2³²

 

 size of each entry is....Max(n,m) bits

therefor ...total size =2³²*16/8 =8Gbytes 

considering carry:- 2³² *17/8 =8.5 Gbytes