1 votes 1 votes A $\text{ROM}$ is used to store the table for Addition of $2$ number of $16$ bit unsigned integers. The size of the $\text{ROM}$ required for the above application in Giga Bytes is _______________. atul_21 asked Jan 1, 2018 • edited Aug 3, 2021 by soujanyareddy13 atul_21 2.6k views answer comment Share Follow See all 16 Comments See all 16 16 Comments reply Show 13 previous comments atul_21 commented Jan 2, 2018 reply Follow Share https://gateoverflow.in/188500/block-replacement-in-cache Bro,plz have a look on this one. 0 votes 0 votes Ashwin Kulkarni commented Jan 2, 2018 reply Follow Share Ohh thanks @shubham I have calculated in bits :( 68Gb = 8.5GB 0 votes 0 votes PiratedVirus commented Dec 10, 2018 reply Follow Share Just small additional info: For all such kinds of questions, Size of ROM = Size of 1 result * Number of all possible results Here, same question but with multiplication https://gateoverflow.in/2725/gate1996-1-21 0 votes 0 votes Please log in or register to add a comment.
Best answer 1 votes 1 votes total entry=216*216=232 size of each entry is....Max(n,m) bits therefor ...total size =232*16/8 =8Gbytes considering carry:- 232 *17/8 =8.5 Gbytes hs_yadav answered Jan 1, 2018 • selected Jan 2, 2018 by atul_21 hs_yadav comment Share Follow See all 0 reply Please log in or register to add a comment.