# doubt

157 views 196.225.168.0/19 and 196.225.184.0/20

196.225.128.0/19 and 196.225.160.0/20

196.225.192.0/20 and 196.225.224.0/19

None of these

0
It should be second part
0
how did u solve that can u explain

1 vote

CIDR Given: 196.255.128.0/18

Here you can see block size 2^14.

So for subnetting we will borrow bit from the host part.

Okk let's expand last two octate ( only last two useful for this question)

196. 255. 1000 0000 . 0000 0000

So here starting 18 bit for BID, and last 14 bit for HID.

Here Half BID wants A organization so take one bit borrow from host part.

So orgn. A= 1/2 CIDR=

196.255. 10 0 00000. 0 = 196.255.128.0/19 ( borrow 1 bit so increase group size by 1bit so 18+1 = 19)

For orgn. B= 1/4 CIDR=

196.255. 10 10 0000. 0= 196.255.160.0/20( borrow 2 bit so increase by two bit 18+2= 20)

If you still feel comfortable to understand comment .

1

Refer this 0
Why are taking two possibility.

How we can find the possibilities.

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