MTU of link = $800B$ (IPHeader + data) $800-20=780$(data)
For Fragmentation offset is stored dividing by 8 $({\frac{780}{8} \neq 0})$
$\therefore$ Units are fragmented as $ (776B \ \times\color{Blue} 5= 3880B )+ (120B \times \color{Blue} 1=\color{RED}{120B} ) = 4000B$
Answer = $6$ Fragments and size = $120$ B