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For a class C network if IP address of a computer is 200.99.39.112 and subnet mask is 255.255.255.224 the decimal value of last octet of last host of sixth subnet is __________

According to me, the answer should be 101 11110 = 190. Because first subnet will have 000, so sixth subnet should have 101.

But the answer given is: 110 11110
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Yes you're correct. It should be 101 1110  = 190.
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they calculate for subnet - 6. but we need to find subnet-5

May  be thay confused in sixes subnet and subnet- 6

you are correct.

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@Anu sir. Subnet - 6 and 6th subnet. Is there any difference?
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example:

Network address = 193.168.1.0 = 11000000.10101000.00000001.00000000
Default subnet for class C = 255.255.255.0 = 11111111.11111111.11111111.00000000

Subnet 0 will be 11000001.10101000.00000001.00000000 = 193.168.1.0
Subnet 1 will be 11000001.10101000.00000001.00100000 = 193.168.1.32
Subnet 2 will be 11000001.10101000.00000001.01000000 = 193.168.1.64
Subnet 3 will be 11000001.10101000.00000001.01100000 = 193.168.1.96
Subnet 4 will be 11000001.10101000.00000001.10000000 = 193.168.1.128
Subnet 5 will be 11000001.10101000.00000001.10100000 = 193.168.1.160
Subnet 6 will be 11000001.10101000.00000001.11000000 = 193.168.1.192

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Thanks @Anu007 and @Ashwin
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i have a doubt... is the total no of subnets in 3 bits = 8 or 6..please tell which to follow?
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@gari It should be 8. 000 to 111

Pls someone can explain in detail the question with solution..Thanks in advance

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