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The r ’s complement of an n-digit decimal number N in base r is defined for all values of N except for N = 0. If the given number is (247)9, then its 9’s complement will be equal to ( _____ )9.

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The r’s complement of an n‐digit number = $r^{n} - N$ for $N \neq 0$

here we need to find 9's complement of $\left ( 247 \right )_{9}$

$\Rightarrow 9^{3} - 247$

$\Rightarrow 1000 - 247$

$\Rightarrow 642$

Note : All above calculation are in base 9

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