1 votes 1 votes Consider the following set of lines :|x|+|y|=1 Area enclosed by them is A)1 B)2 C)3 D)4 Quantitative Aptitude engineering-mathematics + – srestha asked Jan 6, 2018 srestha 438 views answer comment Share Follow See all 7 Comments See all 7 7 Comments reply Show 4 previous comments srestha commented Jan 6, 2018 reply Follow Share but if we solve with square each side is 1 So, 12=1 where is wrong in it? 0 votes 0 votes gauravkc commented Jan 6, 2018 reply Follow Share Each side is not 1. A side would be hypotenuse of the right angled triangle with sides 1 and 1. By pythagoras, it would be √2 1 votes 1 votes srestha commented Jan 6, 2018 reply Follow Share oh yes , thanks :) 0 votes 0 votes Please log in or register to add a comment.
Best answer 1 votes 1 votes Area= $(\sqrt{2})^{2}$ = 2 vijay_jr answered Jan 6, 2018 • selected Jan 6, 2018 by srestha vijay_jr comment Share Follow See all 0 reply Please log in or register to add a comment.