2 votes 2 votes I'm getting too large values :( Computer Networks sliding-window + – Pawan Kumar 2 asked Jan 6, 2018 Pawan Kumar 2 461 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments Ashwin Kulkarni commented Jan 6, 2018 reply Follow Share No need to do it. Tp = 18000 microsec Tt = 64*8/1.536 microsec = 333.333 Sender Ws= 1+2a = 1+ 2*18000/333.33 = 1+108 = 109 Seq number = Ws + Wr In GBN = 109 + 1 = 110 , hence bits =7 In SR = 109+109 = 218, hence bits = 8 4 votes 4 votes Pawan Kumar 2 commented Jan 6, 2018 reply Follow Share one more doubt sir.... in the question isn't speed given in wrong units .... i mean it should be km/microsec 0 votes 0 votes Ashwin Kulkarni commented Jan 6, 2018 reply Follow Share I just solved using units, I mean KM * microsec/KM = microsec. Given thing cannot be speed it should be time per km. 0 votes 0 votes Please log in or register to add a comment.