Segmented Pagging

Question

Consider a system using segmented paging architecture. The segment is divided into 1K pages and each page is having 512entries. The segment number requires 13 bits to represent all the segments of LAS, and the frame number requires 18 bit to represent all the frame of PAS. The memory is word addressable and page table entry is 4 Word.

Then what is the size of each page table?

What is the size of all page tables?

Comments

is ans available?

each page table and all page table

what do u mean by it?

Answer 1

(a). in segmented paging there is maintained a page table for each segment.

no of pages for each segment is given 1 k. and also page table entry size is given as 4 Words.

so page table size for each segment can be defined as => no of pages*page table entry size

                                                                                                  =>1 K * 4 words

                                                                                                  => 4 KW

(b).  segment number requires 13 bits to represent all the segments of LAS . so i think there will be total 2^13 segments and the same no of page tables . so total size of all page table =>   2^13* one page table size

                                                                                       =>   2^13*  4 KW

                                                                                       =>    32 MW

plz someone correct it if wrong .thank you

Comments

32 KW not 32 MW

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To maintain 1 "pagetable" we have to maintain 4 pages because the size of pagetable will be "512 * 4 Words" which is greater than the page size itself.

Correct me if I'm wrong.