L1 = { ε , abc , aabbcc ,aaabbbccc,aaaabbbbcccc , aaaaaabbbbbbcccccc ......}
L2 = { ε , aabbcc ,aaaabbbbcccc ,aaaaaabbbbbbcccccc,........}
L3 = { ε , aabbc ,aaaabbbbcc , aaaaaabbbbbbccc, ...................}
see L2 contains aabbcc but L3 cannot generate aabbcc therefore L2 ⊄ L3 OPTION2 right