2 votes 2 votes For a fixed baud rate, Manchester encoding communication bits twice as fast as NRZ. True or False? Please explain anyone. atul_21 asked Jan 9, 2018 atul_21 800 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Ashwin Kulkarni commented Jan 9, 2018 i edited by Ashwin Kulkarni Jan 10, 2018 reply Follow Share It is false In manchester encoding, baud rate = 2 * bit rate(ME) [means for 1 bit there will be 2 levels of voltage] In NRZ, for 1 bit there will be only one voltage level (high/low) baud rate = 1 * bit rate(NRZ) Comparing both 2* bit rate of (ME) = 1*bit rate (NRZ) 0 votes 0 votes atul_21 commented Jan 10, 2018 reply Follow Share It was given false. I don't get them 0 votes 0 votes Ashwin Kulkarni commented Jan 10, 2018 reply Follow Share I'm confused with the equations okay yes please check the last equation which I derived. bit rate (NRZ) = 2 * bit rate (ME) That means ME is 1/2 fast as NRZ. Hence it is false 2 votes 2 votes atul_21 commented Jan 10, 2018 reply Follow Share Now it seems correct 0 votes 0 votes Please log in or register to add a comment.
