Numerical on AIMD

Question

In TCP, MSS is 8B. If during the 5th RTT the network is congested and timeout occurs, by using AIMD then the threshold value is _________(in Bytes). (assume inital congestion window size is 1 MSS )

Comments

If the answer to my 1st doubt is yes then why has the explanation to this question started with 2 MSS(inital MSS) after transmission 1 -> https://gateoverflow.in/2156/gate2012_45

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Slow start Algorithm and AIMD are completely different ..... as the question above state the use of AIMD, MSM is gradually increasing by  1 and not exponentially(2^n)(slow start).

For reference see the below video... :)

https://www.youtube.com/watch?v=lnS7p0LILq8

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@Nandkishor3939

Thanks for pointing it out :)

Please help me in this..

Initially 1 MSS is sent i.e. 1st transmission should be MSS=1.

After getting back Ack for it after 1 RTT, we will send MSS=2 in 2nd transmission.

After 2 RTT, MSS=3

After 3 RTT, MSS=4

After 4 RTT, MSS=5

Now when this 5 MSS is sent then the time out occurs i.e. during the 5th RTT. Then how can we send MSS=6 now?

 

Answer 1

Yes, you have a point because I have gone through many numericals it  clearly follows what you said . So, in the 5th transaction when MSS=5 there will be time out. Which concludes that new

threshold =( 1/2 * 5  * 8 B ) = 20B 

I think, the question formulation is wrong.