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Given disk size is 40 MB.Block Size is 8KB .The size of the bit map is ..... bits.

Plz describe the answer with a proper diagram so that I could visualize the things as I faces problem when it comes to disks and blocks and hence it went wrong.

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The transferable unit in disks are blocks .

Given that a complete harddisk is of size $40$ MB which is basically collection of many blocks.

So,

Step $1)$ No. of blocks which is $\Large \frac{Total \  size}{size \ of \ a \ block}$  $=\Large \frac{40MB}{8KB}$ $=5$K blocks

Step $2)$ In free space mgmt every block is assigned a bit so total no of bits needed $=5$ Kb$\ =\color{Red}{5 \times 1024}$

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