4 votes 4 votes If $1,-2,3$ are the eigen values of the matrix $A$ then ratio of determinant of $B$ to the trace of $B$ is_______where $B=[adj(A)-A-A^{-1}-A^{2}]$ Linear Algebra engineering-mathematics linear-algebra matrix + – Lakshman Bhaiya asked Jan 10, 2018 • retagged Nov 15, 2018 by Lakshman Bhaiya Lakshman Bhaiya 1.0k views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Pawan Kumar 2 commented Jan 10, 2018 i edited by Pawan Kumar 2 Jan 10, 2018 reply Follow Share is it -3:2? 0 votes 0 votes Lakshman Bhaiya commented Jan 10, 2018 reply Follow Share this is the answer 0 votes 0 votes Ashwin Kulkarni commented Jan 10, 2018 reply Follow Share Apply, $AdjA = \frac{|A|}{A}$ and $A^{-1} = \frac{1}{A}$ Then for each value of $A$ you will get $B = -7, \frac{1}{2}, \frac{-41}{3}$ Computing Determinanat = 47.6 Computing Trace = -20.17 Hence by dividing you will get = -2.3 2 votes 2 votes Aditya Tewari commented Jan 10, 2018 reply Follow Share @ashwin can you please elaborate how you are calculating B,it would be of great help to me...little dense in linear algebra :p 0 votes 0 votes MIRIYALA JEEVAN KUMA commented Jan 18, 2018 reply Follow Share @aditya pls check this https://math.stackexchange.com/questions/100161/eigenvalues-of-adjoint-of-non-singular-matrix 1 votes 1 votes Bhuvi commented Oct 1, 2020 reply Follow Share B=[ adjA - A + A^-1 - A^2] if i put plus sign before the inverse term, i get the right answer. But the question is not that! * I tried with negative sign and get the wrong answer. Please explain?. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Please rotate it :p MiNiPanda answered Jan 10, 2018 MiNiPanda comment Share Follow See all 0 reply Please log in or register to add a comment.