Numbers could be any one of
$\{(1,1,1,1,1,1,1,1,1,1),(1,1,1,1,1,1,1,1,2),(1,1,1,1,1,1,2,2),$
$(1,1,1,1,2,2,2),(1,1,2,2,2,2),(2,2,2,2,2)\}$
So, the number of ${10}$ pennants $=1+ \frac{9!}{8!} + \frac{8!}{6!2!} +\frac{7!}{4!3!} + \frac{6!}{2!4!} +1 =89.$