4 votes 4 votes Probability engineering-mathematics probability + – Lakshman Bhaiya asked Jan 11, 2018 Lakshman Bhaiya 349 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Anu007 commented Jan 11, 2018 reply Follow Share Probability of HIT Target = 1/4 Probability of Not HIT Target = 1- 1/4 = 3/4 so NOT hit in 4 target= $\frac{3}{4}\times \frac{3}{4}\times \frac{3}{4}\times \frac{3}{4} = \frac{81}{256}$ 0 votes 0 votes Lakshman Bhaiya commented Jan 11, 2018 reply Follow Share if hit at least one target then answer is 175/256? if I'm right? 0 votes 0 votes Anu007 commented Jan 11, 2018 reply Follow Share yes... 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes P(hit) = 1/4 P(not hit) = 1- 1/4 = 3/4 P(finall prob of not hit ) = 3/4*3/4*3/4 =81/256 Option C Anish Dahiya answered Feb 18, 2018 Anish Dahiya comment Share Follow See all 0 reply Please log in or register to add a comment.