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ISRO2011-6

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Best answer
10 votes
10 votes
(X⊕Y)⊕Y=(XY'+XY')Y'+(XY+X'Y')Y

               =XY'+XY

               =X

Another way to solve problem

XOR operation is associative

(X⊕Y)⊕Y=X⊕(Y⊕Y)

              =X⊕0

               =X
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2 votes
2 votes
X   Y   Xxor Y=C       Cxor Y=result

0   0     0                      0=X

0   1     1                      0=X

1   0     1                      1=X

1   1     0                      1=X

Therefore, answer is X.(An easy way to solve this type of question or if number of variables is restricted to 3.
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1 votes
1 votes

(X⊕Y)⊕Y = (X⊕Y)Y' + (X⊕Y)'Y =  (X⊕Y)Y'  +  (X⊙Y)Y = (X'Y + XY')Y + (XY + X'Y')Y

                                                                                 = X'Y + XY = (X'+X)Y = Y  

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