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Problem:- here Johnson counter initial state is 101 but 3-bit jhonson counter isequence is like this...(000 100 110 111 011 001)

+1
i am getting 7 .. is it correct
+2
getting $7$ as answer
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@saxena @Anu sir.
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$T$ Flipflop sequence $1\rightarrow0\rightarrow1\rightarrow0\rightarrow1\rightarrow0$ so $Q'=1$ enabled

$Johnson$ Counter : $101\rightarrow010\rightarrow101\rightarrow010\rightarrow101\rightarrow010(Q_2Q_1Q_0)$

$Ring$ Counter : $1010\rightarrow0101\rightarrow1010\rightarrow0101\rightarrow1010\rightarrow0101(Q_3Q_2Q_1Q_0)$

$\{f,b,d\}$ are enabled. making $7$ as decimal value.