It's an AP $10,20,.......190$

The average of an AP=$\frac{a_1+a_n}{2}=\frac{190+10}{2}$

The average of an AP=$\frac{a_1+a_n}{2}=\frac{190+10}{2}$

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a=10

l=190

number of term=19

average of multiplae of 10= (n/2(2a+(n-1)d))/n

(2*10+18*10)/2=100

ans=100

l=190

number of term=19

average of multiplae of 10= (n/2(2a+(n-1)d))/n

(2*10+18*10)/2=100

ans=100

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