A certain population of ALOHA users manages to generate 70 request/sec. If the time is slotted in units of 50 msec, then channel load would be
Explanation: In slotted ALOHA we divide the time into slots and force the station to send only at the beginning of the time slot. Here slot time is 50 ms, so number of slots in 1 second = 1/(50 X 10^-3) => 20 slots/sec
Answer is (B) part.
70 request per second so number of request in one time slot(50 ms) will be (70*50)/1000 = 3.5 (which is channel load means request per time slot)