1 votes 1 votes If A $4$ B long PC-relative branch instruction is stored at location in memory at $(920)_{10}$. The branch is located at $(724)_{10}$. Then Signed displacement present in instruction is $?$ Mention you answer in decimal please! CO and Architecture co-and-architecture + – saxena0612 asked Jan 15, 2018 • edited Mar 14, 2019 by Naveen Kumar 3 saxena0612 685 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Ashwin Kulkarni commented Jan 15, 2018 reply Follow Share - 200...?? 1 votes 1 votes MiNiPanda commented Jan 15, 2018 reply Follow Share For PC relative addressing, Destination address= PC + offset 724= PC + offset PC= address of the next instruction i.e. current address+ 4B =920+4 =924. Offset = 724-924= -200. 3 votes 3 votes joshi_nitish commented Jan 15, 2018 reply Follow Share $-200$ is correct 2 votes 2 votes saxena0612 commented Jan 15, 2018 reply Follow Share Yes $-200$ is correct I was bit confused with $4$ byte long instruction which mean next instruction will be at $924$.Thanks ! 0 votes 0 votes Please log in or register to add a comment.
