19 votes 19 votes The ratio of male to female students in a college for five years is plotted in the following line graph. If the number of female students doubled in $2009$, by what percent did the number of male students increase in $2009$? Quantitative Aptitude gatecse-2014-set2 quantitative-aptitude data-interpretation numerical-answers normal + – go_editor asked Sep 28, 2014 • edited Jun 7, 2018 by Milicevic3306 go_editor 6.2k views answer comment Share Follow See 1 comment See all 1 1 comment reply mehul vaidya commented Apr 2, 2019 reply Follow Share this question is ambiguous , it does not mention whether reading taken on 1 Jan or 31 Dec of particular year. 0 votes 0 votes Please log in or register to add a comment.
Best answer 29 votes 29 votes In 2008 $\dfrac{M}{F}$ ratio is $2.5$ Assume $250$ Males, $100$ Females. In 2009 $\dfrac{M}{F}$ ratio is $3.$ Also total no of females doubled Females $=100\times 2 = 200.$ So, $\dfrac{M}{F} = 3 \implies \dfrac{M}{200}= 3$ $\implies M = 200\times 3 = 600.$ Increase in Male Students $= 600 - 250 = 350$ Increase $=\left(\dfrac{350}{250}\right)\times 100 \%= 140 \%$ Akash Kanase answered Nov 28, 2015 • edited Jun 8, 2018 by Milicevic3306 Akash Kanase comment Share Follow See all 4 Comments See all 4 4 Comments reply Prasanna commented Dec 26, 2015 reply Follow Share why you assumed Male as 250 and female 100. shall we assume both male and female as 100 ? 0 votes 0 votes shikharV commented Jan 22, 2016 reply Follow Share Then male: female ratio will not be 2.5. So, this is a wrong choice. 0 votes 0 votes Registered user 31 commented Jan 24, 2017 reply Follow Share Why are we doing the step "Increase in Male Students = 600 - 250 = 350" consider a case where 100 increased to 300, it should be called a 300% increase, right ? Similarly if 250 increased to 600, should it not be called (600/250)*100 % increase ? 0 votes 0 votes Rupendra Choudhary commented Jan 30, 2018 reply Follow Share $Year$ $2008$ :- Let Male$=$$M_{1}$ and Female$=$$F_{1}$ Given $\frac{M_{1}}{F_{1}}=2.5$ -------->>>Equation 1 $Year$ $2009$ :- Let Male$=$$M_{2}$ and Female$=$$F_{2}$ Given $\frac{M_{2}}{F_{2}}=3$ ---------->>>Equation 2 Given $F_{2}=2*F_{1}$ ---------->>>Equation 3 From Equation 1 : $M_{1}=2.5F_{1}$ From Equation 2 and 3 : $M_{2}=3F_{2}=6F_{1}$ So % increase in number of males=$(\frac{New value-Old value}{old value})*100$ $=(\frac{6F_{1}-2.5F_{1}}{2.5F_{1}})*100=140$% 14 votes 14 votes Please log in or register to add a comment.
10 votes 10 votes In 2008, Let M males and F females be there, so M/F = 2.5 , so M= 2.5F In 2009, as females doubled M/2F = 3, so M = 6F So increase in M is (6F- 2.5F) = 3.5F So percentage increase, (3.5F/2.5F ) * 100 = 140% ShamikBanerjee answered Feb 24, 2019 • edited Jan 21, 2020 by ShamikBanerjee ShamikBanerjee comment Share Follow See all 3 Comments See all 3 3 Comments reply JashanArora commented Jan 20, 2020 reply Follow Share Upvoted. Yours is a good, generalised answer. Maybe change the font to make it more readable, though. 0 votes 0 votes ShamikBanerjee commented Jan 21, 2020 reply Follow Share updated fonts. 0 votes 0 votes nocturnal123 commented Mar 21, 2021 reply Follow Share In “M/2F = 3”, you included 2F, since it is mentioned in question that number of female students is getting doubled. Why are you not including the fact, that M has also change by some “x”, factor. I think, there should be “xM/ 2F = 3 ” ! 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes https://gateoverflow.in/?qa=blob&qa_blobid=8558332009058325329 nocturnal123 answered Mar 21, 2021 nocturnal123 comment Share Follow See all 0 reply Please log in or register to add a comment.