3 votes 3 votes Say the receiver host B, has a buffer size of 4500 bytes and 1500 bytes of received and unprocessed data. If the value of congestion window is 3500 bytes then what will be the size of the window for sender host A?( Marks: -0.33 ) 3500 B 4500 B 4000 B 3000 B Explanation: The size of window is the smaller of the receiver and congestion window which is 3000B as congestion window is 3500 B and receiver window is 4500-1500 = 3000B Can anyone please explain it in details about congestion window? Computer Networks tcp congestion-control + – ankit_thawal asked Jan 15, 2018 ankit_thawal 731 views answer comment Share Follow See 1 comment See all 1 1 comment reply MiNiPanda commented Jan 15, 2018 reply Follow Share It is a fact that the sender's window size is determined by the receiver-advertised window as well as the congestion in the network. So you need to know this point :- The actual size of sender side window = min of ( receiver window size, congestion window size) Here, receiver window size i.e. space available in the buffer =4500-1500=3000 and congestion window size =3500 Hence 3000. 3 votes 3 votes Please log in or register to add a comment.
0 votes 0 votes So 1500B has been revieved by reciever B, hence the buffer size decreases 4500-1500=3000B. Now the TCP window size will be min (CnWd, RWnd) ie min (3500,3000)= 3000B. Hence option 4. rish1602 answered May 2, 2021 rish1602 comment Share Follow See all 0 reply Please log in or register to add a comment.