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+1
Is it 64?
0
Yes. Share your approach pls :)
+1
At clock cycle=8, $I_{6}$'s execute instruction will end and hence at clock cycle=9, $I_{12}$'s Stage 1 will start and $I_{12}$ will complete at clock cycle=12. Now the remaining $I_{13}$ to $I_{16}$ instructions will complete at clock cycle=16. Since, cycle time of pipeline is 4 ns, hence Time Required =

4ns * 16 = 64 ns

After completion of S3 stage of I6, we can know that the next instruction is I12. So the S1 stage of I12 can start only after the S3 of I6.

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thanks