edited by
9,951 views
23 votes
23 votes

At what time between $6$ a. m. and $7$ a. m. will the minute hand and hour hand of a clock make an angle closest to $60^{\circ}$?

  1. $6: 22$ a.m.
  2. $6: 27$ a.m.
  3. $6: 38$ a.m.
  4. $6: 45$ a.m.
edited by

9 Answers

Best answer
42 votes
42 votes
At $6$ a.m. the hour hand and minute hand are separated by $180$ degree. Now,

Speed of hour hand $=360$ degree$/12$ hour (clock is $12\;\text{hrs}$ as am/pm is given) $=30$ degrees $/$hr $=0.5$ degree per minute

Speed of minute hand $=360$ degree per $60$ minutes $=6$ degrees per minute.

So, we want the relative distance between minute and hour hand to be $60$ degree as per question which would mean a relative distance traversal of $180-60 = 120$ degrees. This happens after $x$ minutes such that $$6x - 0.5x = 120 \implies x = \frac{120}{5.5} = 21.81$$ So, closest time is $6:22$ a.m.

Correct Answer: $A$
edited by
46 votes
46 votes

Answer = option A

Hour hand moves 0.5° in 1 minute
Minute hand moves 6° in 1 minute

In $x$ time minute and hour hand have moved. Now, from the figure it is deducible that:

$\color{blue}{6x} + 60 = 180 + 0.5x$

$\implies5.5x = 120$

$\implies x = \frac{120}{5.5} = 21.8181 \approx 22.$

5 votes
5 votes
there was also formula

2/11(30*x + A) or 2/11(30*x - A)

here x is starting time (here x=6)

A is angle

now put the value

2/11(30 * 6 + 60) or 2/11(30 * 6 - 60)

480/11 or 240/11

43.63 or 21.81

So  closest time is 6:22 a.m.
5 votes
5 votes

Correct Option: (A)

TECHNIQUE 1:-
For Hour Hand
1 hour = 5 places covered= 5 * (360 / 60) degree covered= 30 degree covered
=> 1 min = (30/60) degree covered = 0.5 degree covered

For Min. Hand
1 hour = 60 places covered= 60 * (360 / 60) degree covered = 360 degree covered
=> 1 min = (360 / 60) = 6 degree covered

Let, at x min. after 6:00 AM, the angle between hour and min hand be 120 degree.

At x min after 6
Angle covered by hour hand = (x * 0.5) degree 
Angle covered by min hand = (x * 6) degree

Therefore, a/q
{(0.5 * x) degree + 180 degree} - {(6 * x) degree} = 60 degree ,(180 degree is added because initial angle between hour and min hand is 180 degree)
On solving the above equation, we get x = 21.81 min = 22 min(approx.)


TECHNIQUE 2:-
For Hour Hand
1 hour = 5 places covered= 5 * (360 / 60) degree covered= 30 degree covered
=> 1 min = (30/60) degree covered = 0.5 degree covered

For Min. Hand
1 hour = 60 places covered= 60 * (360 / 60) degree covered = 360 degree covered
=> 1 min = (360 / 60) = 6 degree covered

Therefore, at every 1 min, the difference between the angles covered by hour hand and min. hand is (6 - 0.5) degree = 5.5 degree
In other words, the min. hand and hour hand move in a manner such that 5.5 degree angular difference is covered every min.

Now, a/q
Initially, angle between hour and minute hand = 180 degree (At 6:00 AM, hour and min. hand are diametrically opposite)

Finally, say x min. after 6:00 AM, angle between hour and min hand = 60 degree

Therefore, angular difference covered in this interval = (180 - 60) degree = 120 degree

Also, angular difference covered in x min if 5.5 degree is covered every min is given by (5.5 * x) degree

Therefore, (5.5. * x) degree = 120 degree
=> x = 21.81 in = 22 min (approx.)

Answer:

Related questions

19 votes
19 votes
3 answers
1
33 votes
33 votes
4 answers
2
go_editor asked Sep 28, 2014
5,515 views
If $x$ is real and $\mid x^2-2x+3 \mid = 11$, then possible values of $\mid -x^3+x^2-x\mid$ include$2, 4$$2, 14$$4, 52$$14, 52$
24 votes
24 votes
2 answers
3
go_editor asked Sep 28, 2014
3,141 views
The value of $\sqrt{12+\sqrt{12+\sqrt{12+\dots}}} $is$3.464$$3.932$$4.000$$4.444$
16 votes
16 votes
4 answers
4