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Can anybody explain in brief how to solve such numericals.

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As execution time of interrrupt driven io depends upon interrupt delay hence interrupt overhead in considered..and for programmed io execution time depends upon speed of io device thus transfer time is considered..

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In programmed I/O, CPU does continuous polling,

To transfer 1B CPU polls for 400 micro-sec of processing (since transfer speed is 20Kbps)

In interrupt mode CPU is interrupted on completion of i\o,

To transfer 1B CPU does 10 micro-sec of processing(since transfer time between other components is negligible).

Gain = 400 / 4 = 40

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